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Popular >

derivative of θcos(θ)+sin(θ)

Solution

derivative of

θ cos (θ) + sin (θ)

Solution

- θ sin (θ) + 2 cos (θ)

Solution steps

\frac{d}{d θ} (θ cos (θ) + sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (θ cos (θ)) + \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (θ cos (θ)) = cos (θ) - θ sin (θ)

\frac{d}{d θ} (sin (θ)) = cos (θ)

= cos (θ) - θ sin (θ) + cos (θ)

Simplify

= - θ sin (θ) + 2 cos (θ)

Popular Examples

integral from 6 to 8 of (98)/((x-6)^3)

\int_{6}^{8} \frac{98}{( x - 6 ) ^{3}} d x

derivative of 7x^3-5x+8

\frac{d}{d x} (7 x^{3} - 5 x + 8)

limit as x approaches 2 of-1.999+2

x \to 2 lim (- 1.999 + 2)

tangent of f(x)=-x^2+4sqrt(x)tangent of

f (x) = - x^{2} + 4 x

integral of (10x-2)/(5x^2-2x)

\int \frac{10 x - 2}{5 x ^{2} - 2 x} d x

Frequently Asked Questions (FAQ)

What is the derivative of θcos(θ)+sin(θ) ?
The derivative of θcos(θ)+sin(θ) is -θsin(θ)+2cos(θ)
What is the first derivative of θcos(θ)+sin(θ) ?
The first derivative of θcos(θ)+sin(θ) is -θsin(θ)+2cos(θ)