What is the derivative of (x-1/(x^2+1)) ?

The derivative of (x-1/(x^2+1)) is (-x^2+2x+1)/((x^2+1)^2)

What is the first derivative of (x-1/(x^2+1)) ?

The first derivative of (x-1/(x^2+1)) is (-x^2+2x+1)/((x^2+1)^2)

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\frac{d}{d x} (\frac{x - 1}{x ^{2} + 1})

\frac{- x ^{2} + 2 x + 1}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 1}{x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 1 ) ( x ^{2} + 1 ) - \frac{d}{d x} ( x ^{2} + 1 ) ( x - 1 )}{( x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (x - 1) = 1

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{1 \cdot ( x ^{2} + 1 ) - 2 x ( x - 1 )}{( x ^{2} + 1 ) ^{2}}

Simplify

\frac{1 \cdot ( x ^{2} + 1 ) - 2 x ( x - 1 )}{( x ^{2} + 1 ) ^{2}} : \frac{- x ^{2} + 2 x + 1}{( x ^{2} + 1 ) ^{2}}

= \frac{- x ^{2} + 2 x + 1}{( x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (\frac{3 x ^{4}}{4})

\int \frac{2 x - 1}{x ^{2} - x - 12} d x

y^{^{''}} + 9 y = 5 e^{x} - 162 x

\int - \frac{x ^{3}}{3} - x^{2} + \frac{4}{3} d x

\frac{d}{d x} (2 arcsin (\frac{x}{2}))

What is the derivative of (x-1/(x^2+1)) ?
The derivative of (x-1/(x^2+1)) is (-x^2+2x+1)/((x^2+1)^2)
What is the first derivative of (x-1/(x^2+1)) ?
The first derivative of (x-1/(x^2+1)) is (-x^2+2x+1)/((x^2+1)^2)