What is the limit as x approaches 0 of (x-1)/(x^3+x) ?

The limit as x approaches 0 of (x-1)/(x^3+x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (x-1)/(x^3+x)

x \to 0 lim (\frac{x - 1}{x ^{3} + x})

diverges

Solution steps

x \to 0 lim (\frac{x - 1}{x ^{3} + x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x - 1}{x ^{3} + x}) = - \infty

x \to 0 - lim (\frac{x - 1}{x ^{3} + x}) = \infty

= diverges

y = sin (5 x) + cos (6 x)

\int \frac{x ^{2}}{x} d x

\frac{d}{d x} (ln (2 x) d x)

y = - \frac{5}{9} x + 5, (4, 11)

\frac{\partial}{\partial x} (e^{1 - x y})

What is the limit as x approaches 0 of (x-1)/(x^3+x) ?
The limit as x approaches 0 of (x-1)/(x^3+x) is diverges