What is the integral from 0 to 3 of 2^x ?

The integral from 0 to 3 of 2^x is 7/(ln(2))

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integral from 0 to 3 of 2^x

\int_{0}^{3} 2^{x} d x

\frac{7}{ln ( 2 )}

Decimal Notation

10.09886 \dots

Solution steps

\int_{0}^{3} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{0}^{3}

Compute the boundaries:

\frac{7}{ln ( 2 )}

= \frac{7}{ln ( 2 )}

n = 0 \sum \infty \frac{n ^{3}}{2 ^{n}}

\int \frac{1}{sin ^{2} ( a ) x} d x

5 x - 2 x

y^{^{'}} = x^{5} + 2 x^{4} - x - 2

t^{\frac{1}{2}}

What is the integral from 0 to 3 of 2^x ?
The integral from 0 to 3 of 2^x is 7/(ln(2))