What is the sum from n=0 to infinity of (n^3)/(2^n) ?

The sum from n=0 to infinity of (n^3)/(2^n) is converges

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sum from n=0 to infinity of (n^3)/(2^n)

n = 0 \sum \infty \frac{n ^{3}}{2 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{n ^{3}}{2 ^{n}}

Apply Series Ratio Test:

converges

= converges

\int \frac{1}{sin ^{2} ( a ) x} d x

5 x - 2 x

y^{^{'}} = x^{5} + 2 x^{4} - x - 2

t^{\frac{1}{2}}

n = 1 \sum \infty \frac{5 ^{n}}{n}

What is the sum from n=0 to infinity of (n^3)/(2^n) ?
The sum from n=0 to infinity of (n^3)/(2^n) is converges