What is the sum from n=1 to infinity of (5^n)/n ?

The sum from n=1 to infinity of (5^n)/n is diverges

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sum from n=1 to infinity of (5^n)/n

n = 1 \sum \infty \frac{5 ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{5 ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

y^{^{''}} - 8 y^{^{'}} + 25 y = 5 x^{3} e^{- x} - 7 e^{- x}

\frac{d}{d x} (\frac{3 x ^{5} + 7}{x ^{3}})

f (x) = e^{x^{6}} - x + 1

\frac{d}{d x} (tan (x^{2}))

What is the sum from n=1 to infinity of (5^n)/n ?
The sum from n=1 to infinity of (5^n)/n is diverges