en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=-x^2+4,y=3x

Solution

area

y = - x^{2} + 4, y = 3 x

Solution

\frac{125}{6}

+1

Decimal Notation

20.83333 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{1} - x^{2} + 4 - 3 x d x

Solve

\int_{- 4}^{1} - x^{2} + 4 - 3 x d x : \frac{125}{6}

The area is:

= \frac{125}{6}

Popular Examples

derivative of (3-x^2/(3+x^2))

\frac{d}{d x} (\frac{3 - x ^{2}}{3 + x ^{2}})

(dy)/(dx)=sqrt(6y)e^{x+9}

\frac{d y}{d x} = 6 y e^{x + 9}

limit as x approaches 0 of (1-1/x)^x

x \to 0 lim ((1 - \frac{1}{x})^{x})

integral from 80 to 90 of (x-80)/(800)

\int_{80}^{90} \frac{x - 80}{800} d x

limit as x approaches 1 of 0/(x-1)

x \to 1 lim (\frac{0}{x - 1})

Frequently Asked Questions (FAQ)

What is area y=-x^2+4,y=3x ?
The answer to area y=-x^2+4,y=3x is 125/6