What is the integral from 80 to 90 of (x-80)/(800) ?

The integral from 80 to 90 of (x-80)/(800) is 1/16

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integral from 80 to 90 of (x-80)/(800)

\int_{80}^{90} \frac{x - 80}{800} d x

\frac{1}{16}

Decimal Notation

0.0625

Solution steps

\int_{80}^{90} \frac{x - 80}{800} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{800} \cdot \int_{80}^{90} x - 80 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{800} (\int_{80}^{90} x d x - \int_{80}^{90} 80 d x)

\int_{80}^{90} x d x = 850

\int_{80}^{90} 80 d x = 800

= \frac{1}{800} (850 - 800)

Simplify

\frac{1}{800} (850 - 800) : \frac{1}{16}

= \frac{1}{16}

x \to 1 lim (\frac{0}{x - 1})

(4 x + 3)^{4} (x + 1)^{- 3}

\frac{\partial}{\partial v} (\frac{v}{u - v})

\frac{d}{d x} (\frac{x ^{3}}{5})

y = x^{2} - 5, (- 3, 4)

What is the integral from 80 to 90 of (x-80)/(800) ?
The integral from 80 to 90 of (x-80)/(800) is 1/16