What is the derivative of (x^3/5) ?

The derivative of (x^3/5) is (3x^2)/5

What is the first derivative of (x^3/5) ?

The first derivative of (x^3/5) is (3x^2)/5

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\frac{d}{d x} (\frac{x ^{3}}{5})

\frac{3 x ^{2}}{5}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{5} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{5} \cdot 3 x^{3 - 1} : \frac{3 x ^{2}}{5}

= \frac{3 x ^{2}}{5}

y = x^{2} - 5, (- 3, 4)

(1, 2), (- 2, - 1)

\int \frac{3 x}{1 - x ^{4}} d x

\int 36 e^{6 x} sin (6 x) d x

\int x \cdot 2 x + 1 d x

What is the derivative of (x^3/5) ?
The derivative of (x^3/5) is (3x^2)/5
What is the first derivative of (x^3/5) ?
The first derivative of (x^3/5) is (3x^2)/5