What is the limit as x approaches 0 of (1+1/(2x))^x ?

The limit as x approaches 0 of (1+1/(2x))^x is Does not exist

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limit as x approaches 0 of (1+1/(2x))^x

x \to 0 lim ((1 + \frac{1}{2 x})^{x})

Does not exist

Solution steps

x \to 0 lim ((1 + \frac{1}{2 x})^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + \frac{1}{2 x})^{x}) = 1

x \to 0 - lim ((1 + \frac{1}{2 x})^{x}) =

Does not exist

= Does not exist

1 - t

\int_{0}^{1} \frac{3 t ^{2}}{1 + t ^{3}} d t

x \to 0 lim (e^{- 2 x})

cos (\frac{x}{3})

\int (2 - x)^{2} d x

What is the limit as x approaches 0 of (1+1/(2x))^x ?
The limit as x approaches 0 of (1+1/(2x))^x is Does not exist