What is the d/(dθ)(-10sin(θ)) ?

The d/(dθ)(-10sin(θ)) is -10cos(θ)

What is the first d/(dθ)(-10sin(θ)) ?

The first d/(dθ)(-10sin(θ)) is -10cos(θ)

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\frac{d}{d θ} (- 10 sin (θ))

- 10 cos (θ)

Solution steps

\frac{d}{d θ} (- 10 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 10 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= - 10 cos (θ)

y = c cos (t) + t^{2} sin (t)

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