What is the derivative of x^4(e^x) ?

The derivative of x^4(e^x) is 4x^3e^x+e^xx^4

What is the first derivative of x^4(e^x) ?

The first derivative of x^4(e^x) is 4x^3e^x+e^xx^4

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derivative of

x^{4} (e^{x})

4 x^{3} e^{x} + e^{x} x^{4}

Solution steps

\frac{d}{d x} (x^{4} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{4}, g = e^{x}

= \frac{d}{d x} (x^{4}) e^{x} + \frac{d}{d x} (e^{x}) x^{4}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (e^{x}) = e^{x}

= 4 x^{3} e^{x} + e^{x} x^{4}

4 sin^{2} (t)

\frac{\partial}{\partial y} (cos (z))

e^{x} y^{^{'}} - e^{x} y = 1 - 2 x

\int \frac{e ^{4 t}}{t} d t

\frac{s - 1}{s ^{2} ( s ^{2} + 1 )}

What is the derivative of x^4(e^x) ?
The derivative of x^4(e^x) is 4x^3e^x+e^xx^4
What is the first derivative of x^4(e^x) ?
The first derivative of x^4(e^x) is 4x^3e^x+e^xx^4