What is the integral from 1 to 2 of e^{ln(x)} ?

The integral from 1 to 2 of e^{ln(x)} is 3/2

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integral from 1 to 2 of e^{ln(x)}

\int_{1}^{2} e^{l n (x)} d x

\frac{3}{2}

Decimal

1.5

Solution steps

\int_{1}^{2} e^{l n (x)} d x

Apply log rule:

a^{l o g_{a} (b)} = b

= \int_{1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{2}

= [\frac{x ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

x y^{^{'}} = (1 - y^{2})^{\frac{1}{2}}

y = \frac{x + 1}{x ^{3} + x - 2}

f (x) = sin (9 ln (x))

x \to 8 lim (x^{(\frac{2}{3})})

x^{^{''}} = k^{2} x

What is the integral from 1 to 2 of e^{ln(x)} ?
The integral from 1 to 2 of e^{ln(x)} is 3/2