What is area 2x^2,2x+6,-2,2 ?

The answer to area 2x^2,2x+6,-2,2 is -(1+5sqrt(13))/3+6sqrt(13)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 2x^2,2x+6,-2,2

area

2 x^{2}, 2 x + 6, - 2, 2

- \frac{1 + 5 13}{3} + 613 + 2

Decimal

17.29072 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 2 x^{2} - (2 x + 6) d x

Solve

\int_{- 2}^{2} 2 x^{2} - (2 x + 6) d x : - \frac{1 + 5 13}{3} + 613 + 2

The area is:

= - \frac{1 + 5 13}{3} + 613 + 2

y^{^{''}} - y^{^{'}} - 30 y = 0, y (0) = 3, y^{^{'}} (0) = - 3

\frac{\partial}{\partial θ} (r (θ) sin (θ))

y = x - x^{3}

y \to 0 lim (\frac{y}{sin ( 5 y )})

x \to 2 lim (x - 4)

What is area 2x^2,2x+6,-2,2 ?
The answer to area 2x^2,2x+6,-2,2 is -(1+5sqrt(13))/3+6sqrt(13)+2