What is the derivative of sin(yx) ?

The derivative of sin(yx) is cos(yx)(x(dy)/(dx)+y)

What is the first derivative of sin(yx) ?

The first derivative of sin(yx) is cos(yx)(x(dy)/(dx)+y)

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\frac{d}{d x} (sin (y x))

cos (y x) (x \frac{d y}{d x} + y)

Solution steps

\frac{d}{d x} (sin (y x))

Apply the chain rule:

cos (y x) \frac{d}{d x} (y x)

= cos (y x) \frac{d}{d x} (y x)

\frac{d}{d x} (y x) = x \frac{d y}{d x} + y

= cos (y x) (x \frac{d y}{d x} + y)

\frac{d}{d t} (1 + t^{2})

\int_{0}^{1} (1 - x) d x

\frac{d}{d x} (5 x^{2} + 4 sin (x))

n = 0 \sum \infty (\frac{n}{n + 2})^{n}

What is the derivative of sin(yx) ?
The derivative of sin(yx) is cos(yx)(x(dy)/(dx)+y)
What is the first derivative of sin(yx) ?
The first derivative of sin(yx) is cos(yx)(x(dy)/(dx)+y)