What is the integral of 1/((sin(x))^2) ?

The integral of 1/((sin(x))^2) is -cot(x)+C

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integral of 1/((sin(x))^2)

\int \frac{1}{( sin ( x ) ) ^{2}} d x

- cot (x) + C

Solution steps

\int \frac{1}{( sin ( x ) ) ^{2}} d x

Rewrite using trig identities

= \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

n = 1 \sum \infty (\frac{2}{3})^{n + 1}

f (x) = sin (x^{2} + 2 x + 3)

y = 2 x^{2} - 1, [0, 1]

y = \frac{x ^{2}}{2 - x ^{2}}

y^{^{''}} + 4 y = x sin (2 x)

What is the integral of 1/((sin(x))^2) ?
The integral of 1/((sin(x))^2) is -cot(x)+C