What is the limit as x approaches 0= of (sin(4x))/6 ?

The limit as x approaches 0= of (sin(4x))/6 is 0

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limit as x approaches 0= of (sin(4x))/6

x \to 0 = lim (\frac{sin ( 4 x )}{6})

0

Solution steps

x \to 0 = lim (\frac{sin ( 4 x )}{6})

Plug in the value

x = 0

= \frac{sin ( 4 \cdot 0 )}{6}

Simplify

\frac{sin ( 4 \cdot 0 )}{6} : 0

= 0

x \to 6 + lim (\frac{cos ( \frac{5 π}{6} )}{ln ( 7 - x )})

H^{\frac{1}{2}}

w \to 3 lim (\frac{( w - 3 )}{( 2 w ^{2} - w - 15 )})

x^{2} y^{^{'}} = x y + 2 x^{2} e^{\frac{y}{x}}

f (x) = - \frac{1}{1 - x}

What is the limit as x approaches 0= of (sin(4x))/6 ?
The limit as x approaches 0= of (sin(4x))/6 is 0