What is the integral from 0 to 13 of 1/(x^{1/4)} ?

The integral from 0 to 13 of 1/(x^{1/4)} is (4*13^{3/4})/3

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integral from 0 to 13 of 1/(x^{1/4)}

\int_{0}^{13} \frac{1}{x ^{\frac{1}{4}}} d x

\frac{4 \cdot 1 3 ^{\frac{3}{4}}}{3}

Decimal Notation

9.12843 \dots

Solution steps

\int_{0}^{13} \frac{1}{x ^{\frac{1}{4}}} d x

Apply the Power Rule

: [\frac{4}{3} x^{\frac{3}{4}}]_{0}^{13}

= [\frac{4}{3} x^{\frac{3}{4}}]_{0}^{13}

Compute the boundaries:

1 3^{\frac{3}{4}} \cdot \frac{4}{3}

= 1 3^{\frac{3}{4}} \cdot \frac{4}{3}

Simplify

= \frac{4 \cdot 1 3 ^{\frac{3}{4}}}{3}

n \to \infty lim (a^{n})

y^{^{'}} = x y^{2} + 2 y^{2}

y^{^{''}} + 4 y = 8 sin (2 t)

\int \frac{1}{x ^{3} 16 - x ^{2}} d x

(t - 5)^{2}

What is the integral from 0 to 13 of 1/(x^{1/4)} ?
The integral from 0 to 13 of 1/(x^{1/4)} is (4*13^{3/4})/3