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Popular >

y^'=xy^2+2y^2

Solution

y^{^{'}} = x y^{2} + 2 y^{2}

Solution

y = - \frac{2}{x ^{2} + 4 x + c _{1}}

Solution steps

y^{'} (x) = x y^{2} + 2 y^{2}

Solve separable ODE:

y = - \frac{2}{x ^{2} + 4 x + c _{1}}

y = - \frac{2}{x ^{2} + 4 x + c _{1}}

Popular Examples

y^{''}+4y=8sin(2t)

y^{^{''}} + 4 y = 8 sin (2 t)

integral of 1/(x^3sqrt(16-x^2))

\int \frac{1}{x ^{3} 16 - x ^{2}} d x

laplacetransform (t-5)^2 laplace transform

(t - 5)^{2}

\int - π d x

sum from n=-4 to infinity of (-4/7)^n

n = - 4 \sum \infty (- \frac{4}{7})^{n}

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy^2+2y^2 ?
The solution for y^'=xy^2+2y^2 is y=-2/(x^2+4x+c_{1)}