What is (\partial)/(\partial t)(1+t) ?

The answer to (\partial)/(\partial t)(1+t) is 1

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(\partial)/(\partial t)(1+t)

\frac{\partial}{\partial t} (1 + t)

1

Solution steps

\frac{\partial}{\partial t} (1 + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (1) + \frac{\partial}{\partial t} (t)

\frac{\partial}{\partial t} (1) = 0

\frac{\partial}{\partial t} (t) = 1

= 0 + 1

Simplify

= 1

f (x) = 4 + 7 x

\frac{d y}{d x} + \frac{2}{x} y = 4 x

\int_{3}^{8} \frac{1}{x ^{2} - 1} d x

y = x^{2} - 6

What is (\partial)/(\partial t)(1+t) ?
The answer to (\partial)/(\partial t)(1+t) is 1