What is the solution for (dx)/(dy)-xy=x^2y^3 ?

The solution for (dx)/(dy)-xy=x^2y^3 is x=(e^{(y^2)/2})/(-e^{(y^2)/2)y^2+2e^{(y^2)/2}+c_{1}}

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(dx)/(dy)-xy=x^2y^3

\frac{d x}{d y} - x y = x^{2} y^{3}

x = \frac{e ^{\frac{y ^{2}}{2}}}{- e ^{\frac{y ^{2}}{2}} y ^{2} + 2 e ^{\frac{y ^{2}}{2}} + c _{1}}

Solution steps

\frac{d x}{d y} - x y = x^{2} y^{3}

Solve Bernoulli ODE:

x = \frac{e ^{\frac{y ^{2}}{2}}}{- e ^{\frac{y ^{2}}{2}} y ^{2} + 2 e ^{\frac{y ^{2}}{2}} + c _{1}}

x = \frac{e ^{\frac{y ^{2}}{2}}}{- e ^{\frac{y ^{2}}{2}} y ^{2} + 2 e ^{\frac{y ^{2}}{2}} + c _{1}}

x \to \infty lim (x^{- e})

f (x) = 2 + \frac{1}{x}, (2, 2.5)

\frac{\partial}{\partial x} (2 e^{x^{6} y})

\int_{0}^{\infty} 8 e^{- x} d x

\int_{0}^{5} \frac{4}{x ^{2}} d x

What is the solution for (dx)/(dy)-xy=x^2y^3 ?
The solution for (dx)/(dy)-xy=x^2y^3 is x=(e^{(y^2)/2})/(-e^{(y^2)/2)y^2+2e^{(y^2)/2}+c_{1}}