What is the tangent of f(x)=2+1/x ,(2,2.5) ?

The tangent of f(x)=2+1/x ,(2,2.5) is y=-1/4 x+3

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tangent of f(x)=2+1/x ,(2,2.5)

tangent of

f (x) = 2 + \frac{1}{x}, (2, 2.5)

y = - \frac{1}{4} x + 3

Solution steps

Find the slope of

f (x) = 2 + \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{2}}

Compute the slope of

f (x) = 2 + \frac{1}{x}

(2, 2.5) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(2, 2.5) : y = - \frac{1}{4} x + 3

y = - \frac{1}{4} x + 3

\frac{\partial}{\partial x} (2 e^{x^{6} y})

\int_{0}^{\infty} 8 e^{- x} d x

\int_{0}^{5} \frac{4}{x ^{2}} d x

\frac{d}{d x} (e^{- x} + e^{x})

n = 4 \sum \infty \frac{1}{n ^{2} + n}

What is the tangent of f(x)=2+1/x ,(2,2.5) ?
The tangent of f(x)=2+1/x ,(2,2.5) is y=-1/4 x+3