What is the derivative of g(x)=sqrt(1-x) ?

The derivative of g(x)=sqrt(1-x) is -1/(2sqrt(1-x))

What is the first derivative of g(x)=sqrt(1-x) ?

The first derivative of g(x)=sqrt(1-x) is -1/(2sqrt(1-x))

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derivative of

g (x) = 1 - x

- \frac{1}{2 1 - x}

Solution steps

\frac{d}{d x} (1 - x)

Apply the chain rule:

\frac{1}{2 1 - x} \frac{d}{d x} (1 - x)

= \frac{1}{2 1 - x} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= \frac{1}{2 1 - x} (- 1)

Simplify

= - \frac{1}{2 1 - x}

y^{^{''}} + y = 0, y (0) = 1, y^{^{'}} (0) = 0

x y^{^{''}} + y^{^{'}} = 20 x

\frac{\partial}{\partial y} (e^{2 x y^{2}} + 3 x)

\int 5 x^{2} ln (x) d x

x = 6 y - y^{2}, x = 0

What is the derivative of g(x)=sqrt(1-x) ?
The derivative of g(x)=sqrt(1-x) is -1/(2sqrt(1-x))
What is the first derivative of g(x)=sqrt(1-x) ?
The first derivative of g(x)=sqrt(1-x) is -1/(2sqrt(1-x))