What is the solution for y^{''}+y=0,y(0)=1,y^'(0)=0 ?

The solution for y^{''}+y=0,y(0)=1,y^'(0)=0 is y=cos(t)

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y^{''}+y=0,y(0)=1,y^'(0)=0

y^{^{''}} + y = 0, y (0) = 1, y^{^{'}} (0) = 0

y = cos (t)

Solution steps

y^{''} (t) + y = 0

Solve linear ODE:

y = cos (t)

y = cos (t)

x y^{^{''}} + y^{^{'}} = 20 x

\frac{\partial}{\partial y} (e^{2 x y^{2}} + 3 x)

\int 5 x^{2} ln (x) d x

x = 6 y - y^{2}, x = 0

\frac{d y}{d x} = e^{5 x + 2 y}

What is the solution for y^{''}+y=0,y(0)=1,y^'(0)=0 ?
The solution for y^{''}+y=0,y(0)=1,y^'(0)=0 is y=cos(t)