What is the solution for (dy)/(dx)=e^{5x+2y} ?

The solution for (dy)/(dx)=e^{5x+2y} is y=-(ln(-2/5 e^{5x}-c_{1}))/2

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(dy)/(dx)=e^{5x+2y}

\frac{d y}{d x} = e^{5 x + 2 y}

y = - \frac{ln ( - \frac{2}{5} e ^{5 x} - c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{5 x + 2 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{5} e ^{5 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{5} e ^{5 x} - c _{1} )}{2}

\frac{2}{s ^{2} + 2}

\frac{d}{d x} (x (x^{4} + 5)^{5})

\int_{0}^{\infty} a e^{- a x} d x

n = 0 \sum \infty ln (n)

n = 0 \sum \infty \frac{3}{1 0 ^{n}}

What is the solution for (dy)/(dx)=e^{5x+2y} ?
The solution for (dy)/(dx)=e^{5x+2y} is y=-(ln(-2/5 e^{5x}-c_{1}))/2