What is the integral from 0 to infinity of ae^{-ax} ?

The integral from 0 to infinity of ae^{-ax} is 1

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integral from 0 to infinity of ae^{-ax}

\int_{0}^{\infty} a e^{- a x} d x

1

Solution steps

\int_{0}^{\infty} a e^{- a x} d x

Compute the indefinite integral:

\int a e^{- a x} d x = - e^{- a x} + C

Compute the boundaries:

\int_{0}^{\infty} a e^{- a x} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

n = 0 \sum \infty ln (n)

n = 0 \sum \infty \frac{3}{1 0 ^{n}}

x^{2} y^{^{''}} - 4 x y^{^{'}} + 4 y = 0

\int (cos^{3} (x) \cdot sin^{- 4} (x)) d x

x \to 0 + lim ((2 x)^{7 x})

What is the integral from 0 to infinity of ae^{-ax} ?
The integral from 0 to infinity of ae^{-ax} is 1