What is the solution for y^{''}+31y=0 ?

The solution for y^{''}+31y=0 is y=c_{1}cos(sqrt(31)t)+c_{2}sin(sqrt(31)t)

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y^{''}+31y=0

y^{^{''}} + 31 y = 0

y = c_{1} cos (31 t) + c_{2} sin (31 t)

Solution steps

y^{''} (t) + 31 y = 0

Solve linear ODE:

y = c_{1} cos (31 t) + c_{2} sin (31 t)

y = c_{1} cos (31 t) + c_{2} sin (31 t)

\frac{d}{d x} (- 8 x^{\frac{1}{2}})

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\frac{d}{d x} (\frac{4 x ^{3} + 1}{x ^{2} - x + 3})

What is the solution for y^{''}+31y=0 ?
The solution for y^{''}+31y=0 is y=c_{1}cos(sqrt(31)t)+c_{2}sin(sqrt(31)t)