What is area y=3x^4-3x^2,y=3x^2 ?

The answer to area y=3x^4-3x^2,y=3x^2 is -(24sqrt(2))/5+8sqrt(2)

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area y=3x^4-3x^2,y=3x^2

area

y = 3 x^{4} - 3 x^{2}, y = 3 x^{2}

- \frac{24 2}{5} + 82

Decimal Notation

4.52548 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 3 x^{4} - 6 x^{2} d x

Solve

\int_{- 2}^{2} 3 x^{4} - 6 x^{2} d x : - \frac{24 2}{5} + 82

The area is:

= - \frac{24 2}{5} + 82

x \to 2 lim (\frac{2 x + 4}{x - 7})

\int_{0}^{\infty} e^{- 0.2 x} d x

\int 1 0^{- 3 x} d x

\frac{d}{d x} ((e^{x})^{3})

\frac{d}{d x} ((x - 1)^{2} sin (\frac{1}{x - 1}))

What is area y=3x^4-3x^2,y=3x^2 ?
The answer to area y=3x^4-3x^2,y=3x^2 is -(24sqrt(2))/5+8sqrt(2)