What is the derivative of 1/3 sin(3x) ?

The derivative of 1/3 sin(3x) is cos(3x)

What is the first derivative of 1/3 sin(3x) ?

The first derivative of 1/3 sin(3x) is cos(3x)

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derivative of

\frac{1}{3} sin (3 x)

cos (3 x)

Solution steps

\frac{d}{d x} (\frac{1}{3} sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= \frac{1}{3} cos (3 x) \cdot 3

Simplify

\frac{1}{3} cos (3 x) \cdot 3 : cos (3 x)

= cos (3 x)

12 x^{3} - 3 y^{2} x^{4} + 1 y^{^{'}} = 0, y (0) = 2

\frac{cos ( x )}{x ^{9}}

\int \frac{1}{u ^{2} - u} d u

x \to - 2 lim (\frac{x ^{3} - 8}{x - 2})

\frac{\partial}{\partial y} (x^{2} + 4 y)

What is the derivative of 1/3 sin(3x) ?
The derivative of 1/3 sin(3x) is cos(3x)
What is the first derivative of 1/3 sin(3x) ?
The first derivative of 1/3 sin(3x) is cos(3x)