What is (\partial)/(\partial y)(x^2+4y) ?

The answer to (\partial)/(\partial y)(x^2+4y) is 4

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(\partial)/(\partial y)(x^2+4y)

\frac{\partial}{\partial y} (x^{2} + 4 y)

4

Solution steps

\frac{\partial}{\partial y} (x^{2} + 4 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 + 4

Simplify

= 4

(7, - 5), (- 2, - 5)

y = 5^{6 x^{2}}

n = 2 \sum \infty \frac{1}{( n + 1 ) ^{2}}

v (t) = \frac{4 t ^{2} + 2}{5 t + 5}

\int (x + 2) 2 - x d x

What is (\partial)/(\partial y)(x^2+4y) ?
The answer to (\partial)/(\partial y)(x^2+4y) is 4