What is the sum from n=0 to infinity}(4^{(2n+1) of)/((-4)^n) ?

The sum from n=0 to infinity}(4^{(2n+1) of)/((-4)^n) is diverges

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sum from n=0 to infinity}(4^{(2n+1) of)/((-4)^n)

n = 0 \sum \infty \frac{4 ^{(2 n + 1)}}{( - 4 ) ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{4 ^{2 n + 1}}{( - 4 ) ^{n}}

Apply Series Ratio Test:

diverges

= diverges

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What is the sum from n=0 to infinity}(4^{(2n+1) of)/((-4)^n) ?
The sum from n=0 to infinity}(4^{(2n+1) of)/((-4)^n) is diverges