What is the integral from 0 to pi of-7sin(x) ?

The integral from 0 to pi of-7sin(x) is -14

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integral from 0 to pi of-7sin(x)

\int_{0}^{π} - 7 sin (x) d x

- 14

Solution steps

\int_{0}^{π} - 7 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 7 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - 7 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= - 7 \cdot 2

Simplify

= - 14

\frac{3}{t}

\int_{4}^{5} \frac{1}{x ^{2} - 1} d x

\frac{\partial}{\partial x} (x \cdot ln (x))

\int 2 π y (8 - y^{\frac{3}{2}}) d y

f (x) = (ln (x))^{3}, at x = 11

What is the integral from 0 to pi of-7sin(x) ?
The integral from 0 to pi of-7sin(x) is -14