What is the integral of 1/(xe^{ln(x))} ?

The integral of 1/(xe^{ln(x))} is -1/x+C

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integral of 1/(xe^{ln(x))}

\int \frac{1}{x e ^{l n (x)}} d x

- \frac{1}{x} + C

Solution steps

\int \frac{1}{x e ^{l n (x)}} d x

Simplify

\frac{1}{x e ^{l n (x)}} : \frac{1}{x ^{2}}

= \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

x \to - 1 lim (1 x^{2})

\frac{d}{d y} (y^{\frac{1}{2}})

\frac{\partial}{\partial x} (1 (x - y) e^{1 y + 2 x^{2}})

f (x) = x

\frac{\partial}{\partial y} (y^{2} + 1)

What is the integral of 1/(xe^{ln(x))} ?
The integral of 1/(xe^{ln(x))} is -1/x+C