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Popular >

ty^'+y=2t

Solution

t y^{^{'}} + y = 2 t

Solution

y = t + \frac{c _{1}}{t}

Solution steps

t y^{'} (t) + y = 2 t

Solve linear ODE:

y = t + \frac{c _{1}}{t}

y = t + \frac{c _{1}}{t}

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\frac{d}{d x} (\frac{25 - x ^{2}}{32 x})

Frequently Asked Questions (FAQ)

What is the solution for ty^'+y=2t ?
The solution for ty^'+y=2t is y=t+(c_{1})/t