What is the limit as h approaches 0 of (2x+h)-2x ?

The limit as h approaches 0 of (2x+h)-2x is 0

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limit as h approaches 0 of (2x+h)-2x

h \to 0 lim ((2 x + h) - 2 x)

0

Solution steps

h \to 0 lim (2 x + h - 2 x)

Plug in the value

h = 0

= 2 x + 0 - 2 x

Simplify

= 0

cos (\frac{1 - e ^{4 x}}{1 + e ^{4 x}})

\int sin (x^{2} - 5) x d x

y^{^{'}} = x^{\frac{2}{3}}

\int_{1}^{e^{4}} \frac{ln ( x )}{x ^{2}} d x

x \to in f ini t o lim (10)

What is the limit as h approaches 0 of (2x+h)-2x ?
The limit as h approaches 0 of (2x+h)-2x is 0