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Popular >

y^'=x^{2/3}

Solution

y^{^{'}} = x^{\frac{2}{3}}

Solution

y = \frac{3}{5} x^{\frac{5}{3}} + c_{1}

Solution steps

y^{'} (x) = x^{\frac{2}{3}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{\frac{2}{3}} d x

\int x^{\frac{2}{3}} d x = \frac{3}{5} x^{\frac{5}{3}} + c_{1}

y = \frac{3}{5} x^{\frac{5}{3}} + c_{1}

Popular Examples

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\int_{1}^{e^{4}} \frac{ln ( x )}{x ^{2}} d x

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x \to in f ini t o lim (10)

(\partial)/(\partial x)(5(y^2-x^2)ln(x+y))

\frac{\partial}{\partial x} (5 (y^{2} - x^{2}) ln (x + y))

t^{2} y^{^{''}} - 2 y = 0

derivative of sin(xcos(3-x^2))

\frac{d}{d x} (sin (x) cos (3 - x^{2}))

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^{2/3} ?
The solution for y^'=x^{2/3} is y= 3/5 x^{5/3}+c_{1}