What is the derivative of arccot(8y) ?

The derivative of arccot(8y) is -8/(64y^2+1)

What is the first derivative of arccot(8y) ?

The first derivative of arccot(8y) is -8/(64y^2+1)

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derivative of

arccot (8 y)

- \frac{8}{64 y ^{2} + 1}

Solution steps

\frac{d}{d y} (arccot (8 y))

Apply the chain rule:

- \frac{1}{( 8 y ) ^{2} + 1} \frac{d}{d y} (8 y)

= - \frac{1}{( 8 y ) ^{2} + 1} \frac{d}{d y} (8 y)

\frac{d}{d y} (8 y) = 8

= - \frac{1}{( 8 y ) ^{2} + 1} \cdot 8

Simplify

- \frac{1}{( 8 y ) ^{2} + 1} \cdot 8 : - \frac{8}{64 y ^{2} + 1}

= - \frac{8}{64 y ^{2} + 1}

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What is the derivative of arccot(8y) ?
The derivative of arccot(8y) is -8/(64y^2+1)
What is the first derivative of arccot(8y) ?
The first derivative of arccot(8y) is -8/(64y^2+1)