What is the tangent of y=(x^4+2/x),(1,3) ?

The tangent of y=(x^4+2/x),(1,3) is y=2x+1

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tangent of y=(x^4+2/x),(1,3)

tangent of

y = (x^{4} + \frac{2}{x}), (1, 3)

y = 2 x + 1

Solution steps

Find the slope of

y = (x^{4} + \frac{2}{x}) : \frac{d y}{d x} = 4 x^{3} - \frac{2}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, 3) : y = 2 x + 1

y = 2 x + 1

\frac{d ^{2}}{d x ^{2}} (ln (x + 1))

\int (x^{2} + 3) ln (2 x) d x

\int \frac{9}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

y = x^{5 x}

\int_{- 1}^{1} (3 t - 5) d t

What is the tangent of y=(x^4+2/x),(1,3) ?
The tangent of y=(x^4+2/x),(1,3) is y=2x+1