What is the tangent of y=2x^2-x^4,(1,1) ?

The tangent of y=2x^2-x^4,(1,1) is y=1

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tangent of y=2x^2-x^4,(1,1)

tangent of

y = 2 x^{2} - x^{4}, (1, 1)

y = 1

Solution steps

Find the slope of

y = 2 x^{2} - x^{4} : \frac{d y}{d x} = 4 x - 4 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(1, 1) : y = 1

y = 1

\frac{d y}{d x} = - 2 x + 3 y - 5

\frac{\partial}{\partial z} (x + y + z)

\int e^{a t} d t

\frac{\partial}{\partial x} (\frac{1}{4} 2^{x} y^{3})

\int \frac{1}{16 + x ^{2}} d x

What is the tangent of y=2x^2-x^4,(1,1) ?
The tangent of y=2x^2-x^4,(1,1) is y=1