What is the solution for y^{''}+9/t y^'+(15)/(t^2)y=0 ?

The solution for y^{''}+9/t y^'+(15)/(t^2)y=0 is y=(c_{1})/(t^3)+(c_{2})/(t^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+9/t y^'+(15)/(t^2)y=0

y^{^{''}} + \frac{9}{t} y^{^{'}} + \frac{15}{t ^{2}} y = 0

y = \frac{c _{1}}{t ^{3}} + \frac{c _{2}}{t ^{5}}

Solution steps

y^{''} (t) + \frac{9}{t} y^{'} (t) + \frac{15}{t ^{2}} y = 0

Solve linear ODE:

y = \frac{c _{1}}{t ^{3}} + \frac{c _{2}}{t ^{5}}

y = \frac{c _{1}}{t ^{3}} + \frac{c _{2}}{t ^{5}}

n = 1 \sum \infty \frac{3 ^{n}}{2 ^{n}}

\frac{\partial}{\partial x} (2 x^{0.5} y^{0.5})

3 x^{2} + 8 x - 25

\int 4 x^{2} + 3 d x

w (z) = \frac{3 z}{1 + 2 z}

What is the solution for y^{''}+9/t y^'+(15)/(t^2)y=0 ?
The solution for y^{''}+9/t y^'+(15)/(t^2)y=0 is y=(c_{1})/(t^3)+(c_{2})/(t^5)