What is the derivative of (ln(x+1)2-e^{x^2}) ?

The derivative of (ln(x+1)2-e^{x^2}) is 2/(x+1)-e^{x^2}*2x

What is the first derivative of (ln(x+1)2-e^{x^2}) ?

The first derivative of (ln(x+1)2-e^{x^2}) is 2/(x+1)-e^{x^2}*2x

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\frac{d}{d x} ((ln (x + 1)) 2 - e^{x^{2}})

\frac{2}{x + 1} - e^{x^{2}} \cdot 2 x

Solution steps

\frac{d}{d x} ((ln (x + 1)) \cdot 2 - e^{x^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x + 1) \cdot 2) - \frac{d}{d x} (e^{x^{2}})

\frac{d}{d x} (ln (x + 1) \cdot 2) = \frac{2}{x + 1}

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= \frac{2}{x + 1} - e^{x^{2}} \cdot 2 x

\int \frac{2}{4 + x ^{2}} d x

y = \frac{1}{x}, y = x, y = 2

\int 2^{x} ln (2) d x

\int x y e^{z} d z

\frac{d y}{d x} = k (y - 80)

What is the derivative of (ln(x+1)2-e^{x^2}) ?
The derivative of (ln(x+1)2-e^{x^2}) is 2/(x+1)-e^{x^2}*2x
What is the first derivative of (ln(x+1)2-e^{x^2}) ?
The first derivative of (ln(x+1)2-e^{x^2}) is 2/(x+1)-e^{x^2}*2x