What is the integral of \sqrt[6]{x^5} ?

The integral of \sqrt[6]{x^5} is 6/11 x^{11/6}+C

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integral of \sqrt[6]{x^5}

\int 6 x^{5} d x

\frac{6}{11} x^{\frac{11}{6}} + C

Solution steps

\int 6 x^{5} d x

6 x^{5} = x^{\frac{5}{6}},

assuming

x \geq 0

= \int x^{\frac{5}{6}} d x

Apply the Power Rule

: \frac{6}{11} x^{\frac{11}{6}}

= \frac{6}{11} x^{\frac{11}{6}}

Add a constant to the solution

= \frac{6}{11} x^{\frac{11}{6}} + C

\frac{d}{d x} (8 e^{- 4 x})

f (x) = 8 x^{4} tan (x)

x \to 1 lim (ln (x + 1))

\frac{d}{d y} (\frac{1}{2} ln (x^{2} + y^{2}))

n = 1 \sum \infty \frac{2 ^{n} x ^{2 n}}{3 ^{n + 1}}

What is the integral of \sqrt[6]{x^5} ?
The integral of \sqrt[6]{x^5} is 6/11 x^{11/6}+C