What is the limit as x approaches 1 of ln(x+1) ?

The limit as x approaches 1 of ln(x+1) is ln(2)

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limit as x approaches 1 of ln(x+1)

x \to 1 lim (ln (x + 1))

ln (2)

Decimal

0.69314 \dots

Solution steps

x \to 1 lim (ln (x + 1))

Plug in the value

x = 1

= ln (1 + 1)

Simplify

= ln (2)

\frac{d}{d y} (\frac{1}{2} ln (x^{2} + y^{2}))

n = 1 \sum \infty \frac{2 ^{n} x ^{2 n}}{3 ^{n + 1}}

\frac{\partial}{\partial x} (4 arctan (\frac{3}{x}))

f (x) = 4 + 5 x^{2}, (0, 4)

y^{^{''}} + 2 y^{^{'}} + 5 y = 8 sin (2 t)

What is the limit as x approaches 1 of ln(x+1) ?
The limit as x approaches 1 of ln(x+1) is ln(2)