What is the integral of (ln(x))/(2x^2) ?

The integral of (ln(x))/(2x^2) is (-ln(x)-1)/(2x)+C

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integral of (ln(x))/(2x^2)

\int \frac{ln ( x )}{2 x ^{2}} d x

\frac{- ln ( x ) - 1}{2 x} + C

Solution steps

\int \frac{ln ( x )}{2 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{ln ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

= \frac{1}{2} (- \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x)

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= \frac{1}{2} (- \frac{ln ( x )}{x} - \frac{1}{x})

Simplify

\frac{1}{2} (- \frac{ln ( x )}{x} - \frac{1}{x}) : \frac{- ln ( x ) - 1}{2 x}

= \frac{- ln ( x ) - 1}{2 x}

Add a constant to the solution

= \frac{- ln ( x ) - 1}{2 x} + C

5 (- csc^{2} (x) + sec^{2} (x))

\frac{4}{u}

1 - e^{-, at}

\int \frac{1}{( x + 2 ) ^{3}} d x

f (x) = \frac{x}{x + 3}

What is the integral of (ln(x))/(2x^2) ?
The integral of (ln(x))/(2x^2) is (-ln(x)-1)/(2x)+C