What is the derivative of y= 6/(x^4)-4/(x^2)-3/x ?

The derivative of y= 6/(x^4)-4/(x^2)-3/x is -(24)/(x^5)+8/(x^3)+3/(x^2)

What is the first derivative of y= 6/(x^4)-4/(x^2)-3/x ?

The first derivative of y= 6/(x^4)-4/(x^2)-3/x is -(24)/(x^5)+8/(x^3)+3/(x^2)

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derivative of

y = \frac{6}{x ^{4}} - \frac{4}{x ^{2}} - \frac{3}{x}

- \frac{24}{x ^{5}} + \frac{8}{x ^{3}} + \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{6}{x ^{4}} - \frac{4}{x ^{2}} - \frac{3}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{6}{x ^{4}}) - \frac{d}{d x} (\frac{4}{x ^{2}}) - \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (\frac{6}{x ^{4}}) = - \frac{24}{x ^{5}}

\frac{d}{d x} (\frac{4}{x ^{2}}) = - \frac{8}{x ^{3}}

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= - \frac{24}{x ^{5}} - (- \frac{8}{x ^{3}}) - (- \frac{3}{x ^{2}})

Simplify

= - \frac{24}{x ^{5}} + \frac{8}{x ^{3}} + \frac{3}{x ^{2}}

\frac{\partial}{\partial x} (x^{2} e^{\frac{y}{x}})

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\int π e^{x} d x

\frac{\partial}{\partial u} (sin (u) sin (v))

\frac{d ^{2}}{d x ^{2}} (8 e^{x})

What is the derivative of y= 6/(x^4)-4/(x^2)-3/x ?
The derivative of y= 6/(x^4)-4/(x^2)-3/x is -(24)/(x^5)+8/(x^3)+3/(x^2)
What is the first derivative of y= 6/(x^4)-4/(x^2)-3/x ?
The first derivative of y= 6/(x^4)-4/(x^2)-3/x is -(24)/(x^5)+8/(x^3)+3/(x^2)