What is (\partial)/(\partial u)(sin(u)sin(v)) ?

The answer to (\partial)/(\partial u)(sin(u)sin(v)) is sin(v)cos(u)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial u)(sin(u)sin(v))

\frac{\partial}{\partial u} (sin (u) sin (v))

sin (v) cos (u)

Solution steps

\frac{\partial}{\partial u} (sin (u) sin (v))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (v) \frac{\partial}{\partial u} (sin (u))

Apply the common derivative:

\frac{\partial}{\partial u} (sin (u)) = cos (u)

= sin (v) cos (u)

\frac{d ^{2}}{d x ^{2}} (8 e^{x})

\int_{0}^{2} x e^{- 3 x} d x

\int \frac{1}{1 - x ^{2}} \cdot ln (\frac{1 + x}{1 - x}) d x

f (x) = 5 x^{2}, at x = 1

\frac{d y}{d x} = 4 (y^{2} + 1)

What is (\partial)/(\partial u)(sin(u)sin(v)) ?
The answer to (\partial)/(\partial u)(sin(u)sin(v)) is sin(v)cos(u)