What is the tangent of f(x)=5x^2,\at x=1 ?

The tangent of f(x)=5x^2,\at x=1 is y=10x-5

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tangent of f(x)=5x^2,\at x=1

tangent of

f (x) = 5 x^{2}, at x = 1

y = 10 x - 5

Solution steps

Find the tangent point:

(1, 5)

Find the slope of

f (x) = 5 x^{2} : \frac{df ( x )}{d x} = 10 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 10

Find the line with slope m=

10

and passing through

(1, 5) : y = 10 x - 5

y = 10 x - 5

\frac{d y}{d x} = 4 (y^{2} + 1)

\frac{1}{4 z - 5}

y = (x^{2} - 35)^{6}, at x = 6

f (x) = \frac{x}{x ^{2} - 2}

3 x \cdot y

What is the tangent of f(x)=5x^2,\at x=1 ?
The tangent of f(x)=5x^2,\at x=1 is y=10x-5