What is the tangent of y=(x^2-35)^6,\at x=6 ?

The tangent of y=(x^2-35)^6,\at x=6 is y=72x-431

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tangent of y=(x^2-35)^6,\at x=6

tangent of

y = (x^{2} - 35)^{6}, at x = 6

y = 72 x - 431

Solution steps

Find the tangent point:

(6, 1)

Find the slope of

y = (x^{2} - 35)^{6} : \frac{d y}{d x} = 12 x (x^{2} - 35)^{5}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 72

Find the line with slope m=

72

and passing through

(6, 1) : y = 72 x - 431

y = 72 x - 431

f (x) = \frac{x}{x ^{2} - 2}

3 x \cdot y

f (x) = 2 x^{3}

\int_{0}^{\frac{π}{4}} 5 tan^{3} (x) d x

t y^{^{'}} + 2 y = t^{2} - t + 1, y (1) = \frac{1}{2}

What is the tangent of y=(x^2-35)^6,\at x=6 ?
The tangent of y=(x^2-35)^6,\at x=6 is y=72x-431