What is the integral from 2 to 4 of (x^3-6x^2+8x) ?

The integral from 2 to 4 of (x^3-6x^2+8x) is -4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 4 of (x^3-6x^2+8x)

\int_{2}^{4} (x^{3} - 6 x^{2} + 8 x) d x

- 4

Solution steps

\int_{2}^{4} x^{3} - 6 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} x^{3} d x - \int_{2}^{4} 6 x^{2} d x + \int_{2}^{4} 8 x d x

\int_{2}^{4} x^{3} d x = 60

\int_{2}^{4} 6 x^{2} d x = 112

\int_{2}^{4} 8 x d x = 48

= 60 - 112 + 48

Simplify

= - 4

\int_{0}^{1} x d x

y = x^{2} + 3 x

e^{3 x}, 1

arctan (\frac{1}{x})

f (x) = \frac{x ^{3} - x ^{2} - 1}{x ^{2}}

What is the integral from 2 to 4 of (x^3-6x^2+8x) ?
The integral from 2 to 4 of (x^3-6x^2+8x) is -4