What is the derivative of 2x^2-8x+11 ?

The derivative of 2x^2-8x+11 is 4x-8

What is the first derivative of 2x^2-8x+11 ?

The first derivative of 2x^2-8x+11 is 4x-8

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derivative of

2 x^{2} - 8 x + 11

4 x - 8

Solution steps

\frac{d}{d x} (2 x^{2} - 8 x + 11)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (11)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (11) = 0

= 4 x - 8 + 0

Simplify

= 4 x - 8

\frac{d}{d x} (x^{2} (x + sin (x))^{5})

2 t sin (π t)

f (x) = x^{2} + 3 x + 2, at x = 3

\frac{d x}{d t} = \frac{x ^{3} - x t ^{2}}{t ^{3}}

h (x) = arcsec (2 x)

What is the derivative of 2x^2-8x+11 ?
The derivative of 2x^2-8x+11 is 4x-8
What is the first derivative of 2x^2-8x+11 ?
The first derivative of 2x^2-8x+11 is 4x-8